\(\int (1-2 x) (2+3 x)^2 (3+5 x)^3 \, dx\) [1181]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [A] (verification not implemented)
   Sympy [A] (verification not implemented)
   Maxima [A] (verification not implemented)
   Giac [A] (verification not implemented)
   Mupad [B] (verification not implemented)

Optimal result

Integrand size = 20, antiderivative size = 40 \[ \int (1-2 x) (2+3 x)^2 (3+5 x)^3 \, dx=108 x+324 x^2+345 x^3-\frac {1111 x^4}{4}-1061 x^5-\frac {1975 x^6}{2}-\frac {2250 x^7}{7} \]

[Out]

108*x+324*x^2+345*x^3-1111/4*x^4-1061*x^5-1975/2*x^6-2250/7*x^7

Rubi [A] (verified)

Time = 0.01 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {78} \[ \int (1-2 x) (2+3 x)^2 (3+5 x)^3 \, dx=-\frac {2250 x^7}{7}-\frac {1975 x^6}{2}-1061 x^5-\frac {1111 x^4}{4}+345 x^3+324 x^2+108 x \]

[In]

Int[(1 - 2*x)*(2 + 3*x)^2*(3 + 5*x)^3,x]

[Out]

108*x + 324*x^2 + 345*x^3 - (1111*x^4)/4 - 1061*x^5 - (1975*x^6)/2 - (2250*x^7)/7

Rule 78

Int[((a_.) + (b_.)*(x_))*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandIntegran
d[(a + b*x)*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && NeQ[b*c - a*d, 0] && ((ILtQ[
n, 0] && ILtQ[p, 0]) || EqQ[p, 1] || (IGtQ[p, 0] && ( !IntegerQ[n] || LeQ[9*p + 5*(n + 2), 0] || GeQ[n + p + 1
, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, c, d, e, f]))))

Rubi steps \begin{align*} \text {integral}& = \int \left (108+648 x+1035 x^2-1111 x^3-5305 x^4-5925 x^5-2250 x^6\right ) \, dx \\ & = 108 x+324 x^2+345 x^3-\frac {1111 x^4}{4}-1061 x^5-\frac {1975 x^6}{2}-\frac {2250 x^7}{7} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.00 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.00 \[ \int (1-2 x) (2+3 x)^2 (3+5 x)^3 \, dx=108 x+324 x^2+345 x^3-\frac {1111 x^4}{4}-1061 x^5-\frac {1975 x^6}{2}-\frac {2250 x^7}{7} \]

[In]

Integrate[(1 - 2*x)*(2 + 3*x)^2*(3 + 5*x)^3,x]

[Out]

108*x + 324*x^2 + 345*x^3 - (1111*x^4)/4 - 1061*x^5 - (1975*x^6)/2 - (2250*x^7)/7

Maple [A] (verified)

Time = 2.13 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.85

method result size
gosper \(-\frac {x \left (9000 x^{6}+27650 x^{5}+29708 x^{4}+7777 x^{3}-9660 x^{2}-9072 x -3024\right )}{28}\) \(34\)
default \(108 x +324 x^{2}+345 x^{3}-\frac {1111}{4} x^{4}-1061 x^{5}-\frac {1975}{2} x^{6}-\frac {2250}{7} x^{7}\) \(35\)
norman \(108 x +324 x^{2}+345 x^{3}-\frac {1111}{4} x^{4}-1061 x^{5}-\frac {1975}{2} x^{6}-\frac {2250}{7} x^{7}\) \(35\)
risch \(108 x +324 x^{2}+345 x^{3}-\frac {1111}{4} x^{4}-1061 x^{5}-\frac {1975}{2} x^{6}-\frac {2250}{7} x^{7}\) \(35\)
parallelrisch \(108 x +324 x^{2}+345 x^{3}-\frac {1111}{4} x^{4}-1061 x^{5}-\frac {1975}{2} x^{6}-\frac {2250}{7} x^{7}\) \(35\)

[In]

int((1-2*x)*(2+3*x)^2*(3+5*x)^3,x,method=_RETURNVERBOSE)

[Out]

-1/28*x*(9000*x^6+27650*x^5+29708*x^4+7777*x^3-9660*x^2-9072*x-3024)

Fricas [A] (verification not implemented)

none

Time = 0.21 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.85 \[ \int (1-2 x) (2+3 x)^2 (3+5 x)^3 \, dx=-\frac {2250}{7} \, x^{7} - \frac {1975}{2} \, x^{6} - 1061 \, x^{5} - \frac {1111}{4} \, x^{4} + 345 \, x^{3} + 324 \, x^{2} + 108 \, x \]

[In]

integrate((1-2*x)*(2+3*x)^2*(3+5*x)^3,x, algorithm="fricas")

[Out]

-2250/7*x^7 - 1975/2*x^6 - 1061*x^5 - 1111/4*x^4 + 345*x^3 + 324*x^2 + 108*x

Sympy [A] (verification not implemented)

Time = 0.02 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.92 \[ \int (1-2 x) (2+3 x)^2 (3+5 x)^3 \, dx=- \frac {2250 x^{7}}{7} - \frac {1975 x^{6}}{2} - 1061 x^{5} - \frac {1111 x^{4}}{4} + 345 x^{3} + 324 x^{2} + 108 x \]

[In]

integrate((1-2*x)*(2+3*x)**2*(3+5*x)**3,x)

[Out]

-2250*x**7/7 - 1975*x**6/2 - 1061*x**5 - 1111*x**4/4 + 345*x**3 + 324*x**2 + 108*x

Maxima [A] (verification not implemented)

none

Time = 0.19 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.85 \[ \int (1-2 x) (2+3 x)^2 (3+5 x)^3 \, dx=-\frac {2250}{7} \, x^{7} - \frac {1975}{2} \, x^{6} - 1061 \, x^{5} - \frac {1111}{4} \, x^{4} + 345 \, x^{3} + 324 \, x^{2} + 108 \, x \]

[In]

integrate((1-2*x)*(2+3*x)^2*(3+5*x)^3,x, algorithm="maxima")

[Out]

-2250/7*x^7 - 1975/2*x^6 - 1061*x^5 - 1111/4*x^4 + 345*x^3 + 324*x^2 + 108*x

Giac [A] (verification not implemented)

none

Time = 0.27 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.85 \[ \int (1-2 x) (2+3 x)^2 (3+5 x)^3 \, dx=-\frac {2250}{7} \, x^{7} - \frac {1975}{2} \, x^{6} - 1061 \, x^{5} - \frac {1111}{4} \, x^{4} + 345 \, x^{3} + 324 \, x^{2} + 108 \, x \]

[In]

integrate((1-2*x)*(2+3*x)^2*(3+5*x)^3,x, algorithm="giac")

[Out]

-2250/7*x^7 - 1975/2*x^6 - 1061*x^5 - 1111/4*x^4 + 345*x^3 + 324*x^2 + 108*x

Mupad [B] (verification not implemented)

Time = 0.04 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.85 \[ \int (1-2 x) (2+3 x)^2 (3+5 x)^3 \, dx=-\frac {2250\,x^7}{7}-\frac {1975\,x^6}{2}-1061\,x^5-\frac {1111\,x^4}{4}+345\,x^3+324\,x^2+108\,x \]

[In]

int(-(2*x - 1)*(3*x + 2)^2*(5*x + 3)^3,x)

[Out]

108*x + 324*x^2 + 345*x^3 - (1111*x^4)/4 - 1061*x^5 - (1975*x^6)/2 - (2250*x^7)/7